Tìm x, biết:
a) x + \(\dfrac{3}{5}\) = \(\dfrac{4}{7}\)
b) x - \(\dfrac{5}{6}\) = \(\dfrac{1}{6}\)
c) \(\dfrac{-5}{7}\) - x = \(\dfrac{-9}{10}\)
d) \(\dfrac{5}{7}\) - x = 10
e) x : ( \(\dfrac{1}{9}\) - \(\dfrac{2}{5}\) ) = \(\dfrac{-1}{2}\)
f) ( \(\dfrac{-3}{5}\) + 1,25 ) x = \(\dfrac{1}{3}\)
g) \(\dfrac{1}{3}\)x + ( \(\dfrac{2}{3}\) - \(\dfrac{4}{9}\) ) = \(\dfrac{-3}{4}\)
Các bn giúp mk nhanh nha. Sáng mai mk phải nộp cho thầy r. Mk sẽ tick...
Đọc tiếp
Tìm x, biết:
a) x + \(\dfrac{3}{5}\) = \(\dfrac{4}{7}\)
b) x - \(\dfrac{5}{6}\) = \(\dfrac{1}{6}\)
c) \(\dfrac{-5}{7}\) - x = \(\dfrac{-9}{10}\)
d) \(\dfrac{5}{7}\) - x = 10
e) x : ( \(\dfrac{1}{9}\) - \(\dfrac{2}{5}\) ) = \(\dfrac{-1}{2}\)
f) ( \(\dfrac{-3}{5}\) + 1,25 ) x = \(\dfrac{1}{3}\)
g) \(\dfrac{1}{3}\)x + ( \(\dfrac{2}{3}\) - \(\dfrac{4}{9}\) ) = \(\dfrac{-3}{4}\)
Các bn giúp mk nhanh nha. Sáng mai mk phải nộp cho thầy r. Mk sẽ tick cho.
a/ \(x+\dfrac{3}{5}=\dfrac{4}{7}\)
\(x=\dfrac{4}{7}-\dfrac{3}{5}\)
\(x=-\dfrac{1}{35}\)
Vậy ....
b/ \(x-\dfrac{5}{6}=\dfrac{1}{6}\)
\(x=\dfrac{1}{6}+\dfrac{5}{6}\)
\(x=1\)
Vậy ....
c/\(-\dfrac{5}{7}-x=\dfrac{-9}{10}\)
\(x=\dfrac{-5}{7}-\dfrac{-9}{10}\)
\(x=\dfrac{13}{70}\)
Vậy .....
d/ \(\dfrac{5}{7}-x=10\)
\(x=\dfrac{5}{7}-10\)
\(x=\dfrac{-65}{7}\)
Vậy ...
e/ \(x:\left(\dfrac{1}{9}-\dfrac{2}{5}\right)=\dfrac{-1}{2}\)
\(x:\dfrac{-13}{45}=\dfrac{-1}{2}\)
\(x=\dfrac{-1}{2}.\dfrac{-13}{45}\)
\(x=\dfrac{13}{90}\)
Vậy ....
f/ \(\left(\dfrac{-3}{5}+1,25\right)x=\dfrac{1}{3}\)
\(0,65.x=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:0,65\)
\(x=\dfrac{20}{39}\)
Vậy ....
g/ \(\dfrac{1}{3}x+\left(\dfrac{2}{3}-\dfrac{4}{9}\right)=\dfrac{-3}{4}\)
\(\dfrac{1}{3}x+\dfrac{2}{9}=\dfrac{-3}{4}\)
\(\Leftrightarrow\dfrac{1}{3}x=\dfrac{-35}{36}\)
\(\Leftrightarrow x=\dfrac{-35}{12}\)
Vậy ...